carloscn / carloscn/structstudy

leetcode832:翻转图像(flipping-an-image)

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Lang-rust Level-easy 一般问题 数组 查找
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Description

### 问题描述

给定一个 n x n 的二进制矩阵 image ,先 水平 翻转图像,然后 反转 图像并返回 结果 。

水平翻转图片就是将图片的每一行都进行翻转,即逆序。

例如,水平翻转 [1,1,0] 的结果是 [0,1,1]。
反转图片的意思是图片中的 0 全部被 1 替换, 1 全部被 0 替换。

例如,反转 [0,1,1] 的结果是 [1,0,0]。
 

示例 1:

输入:image = [[1,1,0],[1,0,1],[0,0,0]]
输出:[[1,0,0],[0,1,0],[1,1,1]]
解释:首先翻转每一行: [[0,1,1],[1,0,1],[0,0,0]];
然后反转图片: [[1,0,0],[0,1,0],[1,1,1]]
示例 2:

输入:image = [[1,1,0,0],[1,0,0,1],[0,1,1,1],[1,0,1,0]]
输出:[[1,1,0,0],[0,1,1,0],[0,0,0,1],[1,0,1,0]]
解释:首先翻转每一行: [[0,0,1,1],[1,0,0,1],[1,1,1,0],[0,1,0,1]];
然后反转图片: [[1,1,0,0],[0,1,1,0],[0,0,0,1],[1,0,1,0]]
 

提示:

n == image.length
n == image[i].length
1 <= n <= 20
images[i][j] == 0 或 1.

来源:力扣(LeetCode)
链接:https://leetcode.cn/problems/flipping-an-image

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