as_sld function
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- Python
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Description
When I go to print my sld out my filter ends up below my symbolizer. Is there any way to avoid since this violates sld styling policies? Here is my code.
mysld = sld.StyledLayerDescriptor()
nl = mysld.create_namedlayer('test')
ustyle = nl.create_userstyle()
fts = ustyle.create_featuretypestyle()
firstRule = fts.create_rule('test',sld.PolygonSymbolizer)
firstRule.create_filter('value', '>', 'T')
print mysld.as_sld(pretty_print=True)
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