apache / apache/openwhisk

When creating an action, how do you set the environment variables for the container?

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Description

I am creating an action using Rust, and I found /bin/compile.py in the default image used by OpenWhisk, which is openwhisk/action-rust-v1.34:nightly. Upon inspecting the code, I noticed that the RELEASE environment variable must be set in os.environ for the compile option to use the release build. However, I don't know how to set this environment variable.

```
def build(tgt_dir):
# support RELEASE
cmd = ["cargo", "build"]
bin_dir = "debug"
if "RELEASE" in os.environ:
cmd += "--release"
bin_dir = "release"
```
How do I set this environment variable?

Contributor guide

Open the contributing guide

Research direction

Start with /bin/compile.py in the action-rust-v1.34:nightly image and the OpenWhisk action configuration documentation. Determine where container environment variables are configured, then verify that setting RELEASE makes the Rust action use the release build. No test or other entry point is mentioned in the issue.

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Assessment

Tech stack
docker, rust
Domain
cloud
Issue type
Documentation
Difficulty
2/5
Estimated time
1-3 hours
Activity status
Stale
Clarity
Needs clarification
Newbie friendliness
35/100

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