oracle多表空间的情况下执行获取快照sql报错

### Check Ahead

- [x] I have searched the [issues](https://github.com/seata/seata/issues) of this repository and believe that this is not a duplicate.

- [ ] I am willing to try to fix this bug myself.

### Ⅰ. Issue Description

我用的是oracle数据库，seata事务模式是AT，这个事务获取快照的时候这个sql语句的第一个字段怎么跟我实际查的表不一样？

### Ⅱ. Describe what happened

_No response_

### Ⅲ. Describe what you expected to happen

_No response_

### Ⅳ. How to reproduce it (as minimally and precisely as possible)

_No response_

### Ⅴ. Anything else we need to know?

_No response_

### Ⅵ. Environment

_No response_

Start by examining Seata's Oracle AT snapshot SQL generation and compare the first selected field with the actual table definition in a multi-tablespace setup. Reproduce the reported snapshot operation against Oracle; done means the generated SQL uses the correct table fields and executes successfully.

Written by the indexing model from the issue text.