[Python] Pyarrow fs incorrectly resolves S3 URIs with white space as a local path
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Description
### Describe the bug, including details regarding any error messages, version, and platform.
Pyarrow fs incorrectly resolves valid S3 URIs with a whitespace as a local path:
```python
from pyarrow.fs import _resolve_filesystem_and_path, FileSystem
uri = "s3://bucket/prefix with space/a=a"
resolved_filesystem, resolved_path = _resolve_filesystem_and_path(uri, None)
resolved_filesystem
```
This causes subsequent calls such as getting the file info to fail:
```python
path_info = resolved_filesystem.get_file_info(resolved_path)
pyarrow.lib.ArrowInvalid: Expected a local filesystem path, got a URI...
```
A quick look into the [method](https://github.com/apache/arrow/blob/main/python/pyarrow/fs.py#L165) indicates that a LocalFilesytem is chosen by default and returned if alternative filesystems are not detected which seems like a dubious strategy...
I assume this is [where](https://github.com/apache/arrow/blob/main/python/pyarrow/fs.py#L179) the S3 filesystem should be detected but a URI containing a whitespace seems to throw an exception although it's valid:
```python
filesystem, path = FileSystem.from_uri(uri)
Cannot parse URI: 's3://bucket/prefix with space/a=a/'
```
### Component(s)
Python
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