[BUG]反序列化时，在一些情况下，有时会出现不正确的结果

### 问题描述
*一个对象JSON.toJSONString()后，再parseObject()回来时，有概率出错。*
**非必现，执行十几次main方法，有可能会出现一次错误的输出。**

### 环境信息
*请填写以下信息：*

- OS信息： [e.g.：Windows11]
- JDK信息： [e.g.：Openjdk 1.8.0_202]
- 版本信息：[e.g.：Fastjson2 2.0.64]

### 重现步骤
*如何操作可以重现该问题：*

```java

//这是AjaxResult 对象
public class AjaxResult implements Serializable {

protected static final String CODE_2000 = "A-200";//成功CODE
protected static final String CODE_4000 = "A-400";//失败CODE

private static final long serialVersionUID = 1L;
private Boolean success = false;
private String msg = "操作失败！";
private String code = CODE_4000;
private Object data;

public AjaxResult() {
}

public AjaxResult(String msg) {
super();
this.setFail(msg);
}

public void setSuccess() {
this.setSuccess("操作成功！");
}

public void setFail() {
this.setFail("操作失败！");
}

public Boolean getSuccess() {
return success;
}

public void setSuccess(String msg) {
this.success = true;
this.msg = msg;
if (null == this.code || this.code.length() == 0) {
this.code = CODE_2000;
}
else if (CODE_4000.equals(this.code)) {
this.code = CODE_2000;
}
}

public void setFail(String msg) {
this.success = false;
this.msg = msg;
if (null == this.code || this.code.length() == 0) {
this.code = CODE_4000;
}
else if (CODE_2000.equals(this.code)) {
this.code = CODE_4000;
}
}

public void setSuccess(Boolean success) {
this.success = success;
}

public String getMsg() {
return msg;
}

public void setMsg(String msg) {
this.msg = msg;
}

public String getCode() {
return code;
}

public void setCode(String code) {
this.code = code;
}

public Object getData() {
return data;
}

public void setData(Object data) {
this.data = data;
}
}

//这是复现步骤
public static void main(String[] args) {

AjaxResult ajaxResult = new AjaxResult();
ajaxResult.setMsg("借方账户余额不足");
ajaxResult.setCode("4102");
ajaxResult.setSuccess(false);

String resultStr = JSON.toJSONString(ajaxResult);
System.out.println("msg1 = " + resultStr);

AjaxResult ajaxResult2 = JSON.parseObject(resultStr, AjaxResult.class);
if (ajaxResult2.getSuccess()) {
String msg = JSON.toJSONString(ajaxResult2);
System.out.println("出问题了 = " + msg);
}
}
```

### 相关日志输出
**非必现，执行十几次main方法，有可能会出现一次这样的输出：**
msg1 = {"code":"4102","msg":"借方账户余额不足","success":false}
出问题了 = {"code":"4102","msg":"false","success":true}

个人分析原因，因字段‘Boolean success; 的set方法被设计成了，导致了这样的问题。
```java
public void setSuccess(String msg) {
this.success = true;
this.msg = msg;
}

public void setSuccess(Boolean success) {
this.success = success;
}
```

Start with the JSON.parseObject(resultStr, AjaxResult.class) call and the reported AjaxResult reproducer, then trace how deserialization chooses between the overloaded setSuccess methods. A regression test should repeat the round trip and verify that success remains false and msg remains "借方账户余额不足" rather than becoming "false".

Written by the indexing model from the issue text.