[FEATURE]关于getDate 方法调用
- Dominant language
- Java
- Stars
- 4.4k
- Forks
- 613
- Avg merge
- 1d 22h
- Merged PRs (30d)
- 6
Description
当json中的时间字段为10位时间戳的时候 new Date 的api无法正确的转换时间
public Date getDate(String key) {
Object value = super.get(key);
if (value == null) {
return null;
}
if (value instanceof Date) {
return (Date) value;
}
if (value instanceof String) {
return DateUtils.parseDate((String) value);
}
if (value instanceof Number) {
long millis = ((Number) value).longValue();
return new Date(millis);
}
return TypeUtils.toDate(value);
}
可以在
if (value instanceof Number) {
long millis = ((Number) value).longValue();
return new Date(millis);
} 这部分增加一个关于时间戳长度的判断
Contributor guide
Research direction
Start at the getDate(String key) entry point and inspect the Number branch shown in the issue. Reproduce conversion of a JSON timestamp with 10 digits, then define the length-based handling so the resulting Date represents the intended time; verify both timestamp-length cases after the change.
Written by the indexing model from the issue text.
Assessment
- Tech stack
- java
- Domain
- backend
- Issue type
- Feature
- Difficulty
- 2/5
- Estimated time
- 1-3 hours
- Activity status
- Stale
- Clarity
- Mostly clear
- Newbie friendliness
- 48/100