[BUG]默认策略下，序列化后的对象，反序列化不回来

### 问题描述
*简要描述您碰到的问题。*
默认策略下，序列化后的对象，反序列化不回来

@Data
@Builder
@AllArgsConstructor
@NoArgsConstructor
@EqualsAndHashCode
public class PortKeyVO {}

String testStr = "{{\"neId\":167773037,\"portId\":14,\"shelfId\":0,\"slotId\":1,\"subSlotId\":-1}:\"4810\",{\"neId\":167772905,\"portId\":4,\"shelfId\":0,\"slotId\":1,\"subSlotId\":-1}:\"4810\"}";
ParserConfig config = new ParserConfig();
config.setAutoTypeSupport(true);
Type type = new TypeReference>(){}.getType();
Map keyVO = JSON.parseObject(testStr, type, config);
System.out.println(com.alibaba.fastjson2.JSON.toJSONString(keyVO, JSONWriter.Feature.WriteClassName));
System.out.println(JSON.toJSONString(keyVO));

String json2Str = "{\"PortKeyVO(neId=167773037, shelfId=0, slotId=1, subSlotId=-1, portId=14)\":\"4810\",\"PortKeyVO(neId=167772905, shelfId=0, slotId=1, subSlotId=-1, portId=4)\":\"4810\"}";
Map keyVO2 = com.alibaba.fastjson2.JSON.parseObject(json2Str, type);

### 环境信息
*请填写以下信息：*

- OS信息： [e.g.：CentOS 8.4.2105 4Core 3.10GHz 16 GB]
- JDK信息： [e.g.：Openjdk 1.8.0_312]
- 版本信息：[e.g.：Fastjson2 2.x.x]

### 重现步骤
*如何操作可以重现该问题：*

1. 使用 `xxx.xxx` 方法
2. 输入 `...` 数据
3. 出现 `...` 错误
```java
//可在此输入示例代码
```

### 期待的正确结果
*对您期望发生的结果进行清晰简洁的描述。*
期待能正常反序列化成正确的map

### 相关日志输出
*请复制并粘贴任何相关的日志输出。*
{"PortKeyVO(neId=167773037, shelfId=0, slotId=1, subSlotId=-1, portId=14)":"4810","PortKeyVO(neId=167772905, shelfId=0, slotId=1, subSlotId=-1, portId=4)":"4810"}
{{"empty":false,"neId":167773037,"portId":14,"shelfId":0,"slotId":1,"subSlotId":-1}:"4810",{"empty":false,"neId":167772905,"portId":4,"shelfId":0,"slotId":1,"subSlotId":-1}:"4810"}
Exception in thread "main" com.alibaba.fastjson2.JSONException: expect ':', but , offset 1, character ", line 1, column 1, fastjson-version 2.0.52 "PortKeyVO(neId=167773037, shelfId=0, slotId=1, subSlotId=-1, portId=14)"
at com.alibaba.fastjson2.JSONReaderUTF16.readFieldNameHashCode(JSONReaderUTF16.java:1374)
at com.alibaba.fastjson2.reader.ORG_1_5_PortKeyVO.readObject(Unknown Source)
at com.alibaba.fastjson2.util.TypeUtils.cast(TypeUtils.java:1510)
at com.alibaba.fastjson2.util.TypeUtils.cast(TypeUtils.java:1409)
at com.alibaba.fastjson2.util.TypeUtils.cast(TypeUtils.java:1404)
at com.alibaba.fastjson2.reader.ObjectReaderImplMapTyped.readObject(ObjectReaderImplMapTyped.java:356)
at com.alibaba.fastjson2.JSON.parseObject(JSON.java:1305)

#### 附加信息
*如果你还有其他需要提供的信息，可以在这里填写（可以提供截图、视频等）。*

fastjson 1.2.X 实现：
{
List propertyFilters = this.propertyFilters;
if (propertyFilters != null && propertyFilters.size() > 0) {
if (entryKey == null || entryKey instanceof String) {
if (!this.apply(serializer, object, (String) entryKey, value)) {
continue;
}
} else if (entryKey.getClass().isPrimitive() || entryKey instanceof Number) {
String strKey = JSON.toJSONString(entryKey);
if (!this.apply(serializer, object, strKey, value)) {
continue;
}
}
}
}

fastjson2.0.52 实现：
for (Map.Entry entry : (Iterable) map.entrySet()) {
Object value = entry.getValue();
if (value == null && !writeNulls) {
continue;
}

Object entryKey = entry.getKey();
String key;
if (entryKey == null) {
key = null;
} else {
key = entryKey.toString();
}

如果我们的Map的key对象没有重写tostring方法，直接无法序列化key
{"vo.port.PortKeyVO@e06f294":"4810","vo.port.PortKeyVO@aeb0a446":"4810"}

Reproduce the shown PortKeyVO map round trip with JSON.parseObject and JSON.toJSONString, comparing the fastjson 1.x behavior included in the issue. Inspect map-key handling at ObjectReaderImplMapTyped.readObject and the serialization entry point, then verify that a map with object keys serializes and deserializes back to the expected keys.

Written by the indexing model from the issue text.