SimpleGrantedAuthority 反序列化报错[BUG]

### 问题描述
*简要描述您碰到的问题。*

登陆授权信息反序列化拿不到属性。1.2.83 正常。

### 环境信息
*请填写以下信息：*

- OS信息： mac
- JDK信息： [e.g.：Openjdk 1.8.0_312]
- 版本信息：[e.g.：Fastjson2 2.0.42]

### 重现步骤
*如何操作可以重现该问题：*

```java
static final Filter autoTypeFilter = JSONReader.autoTypeFilter(
// 按需加上需要支持自动类型的类名前缀，范围越小越安全
"org.springframework.security.core.authority.SimpleGrantedAuthority"
);

public static void main(String[] args) {
System.out.println(JSON.parseObject("\n" +
" {\"@type\": \"org.springframework.security.core.authority.SimpleGrantedAuthority\",\n" +
" \"authority\": \"dept:add\"\n" +
" }", SimpleGrantedAuthority.class, autoTypeFilter));
}
```

### 期待的正确结果
*对您期望发生的结果进行清晰简洁的描述。*

正确结果打印出：dept:add

### 相关日志输出
*请复制并粘贴任何相关的日志输出。*

Exception in thread "main" java.lang.IllegalArgumentException: A granted authority textual representation is required
at org.springframework.util.Assert.hasText(Assert.java:289)
at org.springframework.security.core.authority.SimpleGrantedAuthority.(SimpleGrantedAuthority.java:39)
at com.alibaba.fastjson2.reader.ConstructorFunction.apply(ConstructorFunction.java:148)
at com.alibaba.fastjson2.reader.ConstructorFunction.apply(ConstructorFunction.java:15)
at com.alibaba.fastjson2.reader.ObjectReaderNoneDefaultConstructor.readObject(ObjectReaderNoneDefaultConstructor.java:327)
at com.alibaba.fastjson2.JSON.parseObject(JSON.java:768)

Run the provided JSON.parseObject example with SimpleGrantedAuthority and inspect the stack-trace path through ConstructorFunction and ObjectReaderNoneDefaultConstructor. Compare the current behavior with fastjson2 1.2.83; done means the authority field deserializes to the expected “dept:add” value without the IllegalArgumentException.

Written by the indexing model from the issue text.