当前版本是否支持字符类型与数字类型的计算？如下代码会报 java.lang.Character cannot be cast to class java.lang.Number

@Test
public void test() throws Exception {

System.out.println('a'<98);
ExpressRunner runner = new ExpressRunner();
String[] expList = new String[]{
" String ocr_address=\"aabbcc\";\n" +
" String busi_address=\"ａａｂｂｃｃ\";\n" +
" if (ocr_address == null || ocr_address == \"\") {\n" +
" System.out.println(false);\n" +
" } else {\n" +
" char[] c = busi_address.toCharArray();\n" +
" for (int i = 0; i < c.length; i++) {\n" +
" if (c[i] == 12288) {\n" +
" c[i] = (char) 32;\n" +
" continue;\n" +
" }\n" +
" if (c[i] > 65280 && c[i] < 65375)\n" +
" c[i] = (char) (c[i] - 65248);\n" +
" }\n" +
" busi_address = new String(c);\n" +
" System.out.println(ocr_address.equals(busi_address));\n" +
" }"
};
IExpressContext context = new DefaultContext();
context.put("test",'a'+0);
for(String exp : expList) {
Object result = runner.execute(exp, context, null, true, false);
System.out.println(result);
assert (true == (Boolean) result);
}
}

Start by running the provided test method and its expressions through ExpressRunner.execute, focusing on the character-to-number comparisons and the reported ClassCastException. Trace the expression evaluation path used by execute to identify where the comparison fails. Done means the supplied character and numeric comparisons execute without the reported cast error and the test assertions pass.

Written by the indexing model from the issue text.