Question: Just parse without need to create a QueryParser (aka rql.MustNewParser)
Aperta
- Lingua principale
- Go
- Stelle
- 367
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Descrizione
As I know, I need to create a parser to be able to parse the query into params. Like:
```go
QueryParser = rql.MustNewParser(rql.Config{
Model: User{},
FieldSep: ".",
})
// and then ...
params, err := QueryParser.Parse(query)
```
What I want is a way to just parse the raw query without care about the other stuff. Something like:
```go
params, err := rql.RawQuery(query)
```
So it will produce the same result as `QueryParser.Parse` but without any aditional steps validating the data, checking struct tags etc.
There is any method to do something like that?
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