Allow hue in `HSVLike.hsvLike` to be outside the range of [0, 1]

As hue represents an angle on a cylinder, it makes sense to allow it to go outside the range - it should just loop back from the "other" side.
To make sure it'll not break much, HSVLike#h() still should return a value in the range. So, instead of checking if the value is in range, it should loop into it internally.
Like 11.3 should be transformed into 0.3, -1.8 into 0.2, etc.

It'd probably be better to also accept h in HSVLike.hsvLike as a double instead of float to make sure the imprecision is not as bad for larger values, but it feels a bit unnatural for it to accept h as double but then return it as float.

Locate HSVLike.hsvLike and HSVLike#h() in the Java sources and read their existing range validation and related tests. Update the hue behavior so values outside [0, 1] wrap into that range while preserving the requested API precision decision, then verify examples such as 11.3 → 0.3 and -1.8 → 0.2.