OpenHFT / OpenHFT/Zero-Allocation-Hashing
How to correctly calculate hash for byte[][]?
Nobody has claimed this yet.
- Dominant language
- Java
- Stars
- 845
- Forks
- 140
- Avg merge
- 12d 38m
- Merged PRs (30d)
- 2
Description
In standard hash functions in Java we can do something like:
Digest digest = new Blake2bDigest(64);
for (int i = 0; i < bytes[0].length; i++) {
digest.update(bytes[0][i], 0, bytes[0][i].length));
}
byte[] hash = new byte[digest.getDigestSize()];
digest.doFinal(hashResult, 0);
return hash;
I understand that it's not possible to have similar API here since the main goal of this project is to have zero allocations. But what will be the correct way to calculate result hash for an array of arrays? Is there any solution except creating one big byte array and put everything into it?
Thanks.
Contributor guide
No contributing guide indexed for this repository
First steps
- Read the whole issue, then the project's contributing guide.
- Comment on the issue to say you are picking it up — it saves two people doing the same work.
- Fork the repository and make your change on a branch.
- Open a pull request that references the issue number.
Research direction
No file, test, or entry point is named. Begin by locating the Java hashing APIs that accept byte arrays and compare their allocation behavior; done would require a decided zero-allocation approach for byte[][] and validation of its resulting hash.
Written by the indexing model from the issue text.
Assessment
- Tech stack
- java
- Domain
- cryptography
- Issue type
- Feature
- Difficulty
- 5/5
- Estimated time
- Over a week
- Activity status
- Stale
- Clarity
- Needs clarification
- Newbie friendliness
- 25/100