[QST] Why does Balanced Kmeans only support random initialization?
Open
Nobody has claimed this yet.
question
- Dominant language
- Cuda
- Stars
- 854
- Forks
- 236
- Avg merge
- 3d 3h
- Merged PRs (30d)
- 62
Description
What is your question?
Does kmeans++ work with balanced kmeans?
Contributor guide
First steps
- Read the whole issue, then the project's contributing guide.
- Comment on the issue to say you are picking it up — it saves two people doing the same work.
- Fork the repository and make your change on a branch.
- Open a pull request that references the issue number.
Research direction
Start by locating the balanced k-means implementation and its initialization configuration, then check whether k-means++ is supported or intentionally excluded. The issue names no files or tests, and the scope is not defined beyond answering whether k-means++ works with balanced k-means.
Written by the indexing model from the issue text.
Assessment
- Domain
- machine-learning
- Issue type
- Feature
- Difficulty
- 4/5
- Estimated time
- 3-5 days
- Activity status
- Stale
- Clarity
- Needs clarification
- Newbie friendliness
- 25/100