MongoEngine / MongoEngine/mongoengine

Trying to do a "join" on a ListField(ReferenceField(...)) doesn't raise an exception

Open
#1,309 6 comments 0 reactions 0 assignees View on GitHub

Nobody has claimed this yet.

(De)Reference Bug
Dominant language
Python
Stars
4.3k
Forks
1.2k
Avg merge
4h 41m
Merged PRs (30d)
11

Description

I have two models, let's say:

class Article(Document):
    title = StringField()
    tags = ListField(StringField())

class Blog(Document):
     articles = ListField(ReferenceField(Article))

I expected that Blog.objects.filter(articles__tags='lemon') would return the list of blogs that have at least one article using the tag lemon, but it just returns an empty set.

Is it the expected behaviour or a bug? Could it be supported?

Regards,

Contributor guide

Open the contributing guide

First steps

  1. Read the whole issue, then the project's contributing guide.
  2. Comment on the issue to say you are picking it up — it saves two people doing the same work.
  3. Fork the repository and make your change on a branch.
  4. Open a pull request that references the issue number.

Research direction

Start by reproducing the issue with the Article and Blog models shown in the report, then run Blog.objects.filter(articles__tags='lemon') against data containing a matching referenced article. Trace how the filter handles ListField(ReferenceField(...)) joins and compare the result with the expected matching blogs. Done means the behavior is documented or the query is supported with coverage for this example.

Written by the indexing model from the issue text.

Assessment

Tech stack
mongodb, python
Domain
backend, databases
Issue type
Bug
Difficulty
4/5
Estimated time
3-5 days
Activity status
Stale
Clarity
Mostly clear
Newbie friendliness
35/100

Get new issues in your inbox

A short digest of beginner-friendly GitHub issues.