MichalLytek / MichalLytek/type-graphql
A way to conditionally hide a field
- Dominant language
- TypeScript
- Stars
- 8.1k
- Forks
- 672
- PR merge metrics
- No merged PRs in 30d
Description
**Describe the issue**
I did read the docs but could not find any feature to conditionally hide a field.
I have a simple use case, Each user in my DB has a email, now in some cases I want to return it in Graphql response and in some not, what is the best way to implement it?
Should that be done just in the resolver, or is there a type-graphql Decorator to hide a field conditionally?
Or maybe I should use a FieldResolver and it will override the original return with what I want?
Contributor guide
Research direction
The issue names no files, tests, or entry points. Start by reviewing the project documentation and the TypeScript GraphQL schema and resolver guidance for conditional field exposure. A complete outcome would need a documented supported approach or an accepted implementation scope, neither of which the issue currently specifies.
Written by the indexing model from the issue text.
Assessment
- Tech stack
- graphql, typescript
- Domain
- api, backend
- Issue type
- Feature
- Difficulty
- 5/5
- Estimated time
- Over a week
- Activity status
- Stale
- Clarity
- Needs clarification
- Newbie friendliness
- 25/100