JuliaData / JuliaData/DataFramesMeta.jl

`@with` macro clashes with `Base.@with` in Julia 1.11+

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Julia
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Description

Julia 1.11 is the first version to export Base.@with:

help?> @with
  @with vars... expr

  Macro version of with(f, vars...) but with expr instead of f function. This is similar to using with with a do block, but avoids creating a closure.

This causes a name conflict with DataFramesMeta.@with (i.e., error when the latter used in a module). MWE:

julia> module Foo
    using DataFrames, DataFramesMeta

    const df = DataFrame(a = [1, 2, 3])
    print() = @with df println.(:a)
end
WARNING: both DataFramesMeta and Base export "@with"; uses of it in module Foo must be qualified
ERROR: LoadError: UndefVarError: `@with` not defined
in expression starting at REPL[14]:6

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First steps

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  2. Comment on the issue to say you are picking it up — it saves two people doing the same work.
  3. Fork the repository and make your change on a branch.
  4. Open a pull request that references the issue number.

Research direction

Start by running the supplied MWE on Julia 1.11+ and inspect how DataFramesMeta.@with is exported and resolved alongside Base.@with. Done means the example module loads and @with evaluates without an unresolved name while preserving DataFramesMeta behavior.

Written by the indexing model from the issue text.

Assessment

Tech stack
julia
Domain
data
Issue type
Bug
Difficulty
5/5
Estimated time
Over a week
Activity status
Stale
Clarity
Needs clarification
Newbie friendliness
25/100

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