JuliaCollections / JuliaCollections/IterTools.jl
IterTools.groupby doesn't group nonconsecutive elements together.
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- Julia
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Description
When I execute the following code:
my_list = [ ["u",1], ["u",2], ["a",1], ["d", 1], ["a",2],["d",2]]
collect(IterTools.groupby(s->s[1], my_list))
I get as output:
[["u", 1], ["u", 2]]
[["a", 1]]
[["d", 1]]
[["a", 2]]
[["d", 2]]
So it seems that the items with key a and d are not properly grouped together.
Environment:
Julia v1.10.9
itertools v1.10.0
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First steps
- Read the whole issue, then the project's contributing guide.
- Comment on the issue to say you are picking it up — it saves two people doing the same work.
- Fork the repository and make your change on a branch.
- Open a pull request that references the issue number.
Research direction
Start by reproducing the provided Julia v1.10.9 example at the IterTools.groupby entry point and inspect its current grouping behavior. Done means items sharing keys across separated runs are grouped together, with the resulting behavior covered by an appropriate test.
Written by the indexing model from the issue text.
Assessment
- Tech stack
- julia
- Domain
- tooling
- Issue type
- Bug
- Difficulty
- 3/5
- Estimated time
- 1-2 days
- Activity status
- Stale
- Clarity
- Mostly clear
- Newbie friendliness
- 45/100