Precedence of pipeline operator with list syntax w/o explicit line continuation

Right now, if I compile this code:

f
  * a
    |> b

the resulting Lua is:

return b(f({ -- 2
  a -- 2
})) -- 2

This is the opposite of what I'd expect: based on the indentation, I would've thought it would be parsed as f({ a|> b }), not f({ a }) |> b. If I use an explicit slash:

f
  * a \
    |> b

then it compiles like I'd expect:

return f({ -- 2
  b(a) -- 2
}) -- 3

I'm not sure if this is intentional? But it was certainly rather confusing 😅

Reproduce the two examples from the issue and compare their generated Lua, first checking the parser or precedence handling for list syntax, pipeline operators, and explicit line continuation. Done means the no-slash form follows the indentation-based interpretation described in the issue, with regression coverage for both forms.