FreeCodeCampChina / FreeCodeCampChina/freecodecamp.cn
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Description
Challenge [Truncate a string](https://freecodecamp.cn/challenges/truncate-a-string#?solution=function%20truncate(str%2C%20num)%20%7B%0A%20%20%2F%2F%20%E8%AF%B7%E6%8A%8A%E4%BD%A0%E7%9A%84%E4%BB%A3%E7%A0%81%E5%86%99%E5%9C%A8%E8%BF%99%E9%87%8C%0A%20%20if(str.length%3Enum)%7B%0A%20%20%20%20if(%20num%20%3E%203%20)%7B%0A%20%20%20%20%20%20str%3Dstr.slice(0%2Cnum-3)%2B%22...%22%3B%0A%20%20%20%20%20%20return%20str%3B%0A%20%20%20%20%7D%20else%20%7B%0A%20%20%20%20%20%20str%3Dstr.slice(0%2Cnum)%2B%22...%22%3B%0A%20%20%20%20%7D%0A%20%20%7D%20else%20%7B%0A%20%20%20%20str%3Dstr.slice(0%2Cnum)%3B%0A%20%20%7D%0A%20%20%20%20%0A%20%20%0A%20%20return%20str%3B%0A%7D%0A%0Atruncate(%22A-tisket%20a-tasket%20A%20green%20and%20yellow%20basket%22%2C%20%22A-tisket%20a-tasket%20A%20green%20and%20yellow%20basket%22.length)%3B%0A) has an issue.
User Agent is: Mozilla/5.0 (Windows NT 6.1; WOW64) AppleWebKit/537.36 (KHTML, like Gecko) Chrome/58.0.3029.110 Safari/537.36 SE 2.X MetaSr 1.0.
Please describe how to reproduce this issue, and include links to screenshots if possible.
My code:
```javascript
function truncate(str, num) {
// 请把你的代码写在这里
if(str.length>num){
if( num > 3 ){
str=str.slice(0,num-3)+"...";
return str;
} else {
str=str.slice(0,num)+"...";
}
} else {
str=str.slice(0,num);
}
return str;
}
truncate("A-tisket a-tasket A green and yellow basket", "A-tisket a-tasket A green and yellow basket".length);
以下为题目:
截断字符串
(用瑞兹来截断对面的退路)
如果字符串的长度比指定的参数num长,则把多余的部分用...来表示。
切记,插入到字符串尾部的三个点号也会计入字符串的长度。
但是,如果指定的参数num小于或等于3,则添加的三个点号不会计入字符串的长度。
鉴于本题3和4两个验证,个人认为,“如果字符串的长度比指定的参数num长,则把多余的部分用...来表示。”后面再加一句:若参数num大于等于字符串长度,则不加...。
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