CodingTrain / CodingTrain/Suggestion-Box
Pi by "throwing darts" at a Gaussian rather than a circle
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Pi Day
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Description
Since the area of a Gaussian is sqrt(pi) _(or sqrt(pi)/2 if from 0 to infinity)_ you can redo the standard "dart" challenge but instead of checking if they are within a circle, you check for random (x,y) that y
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