How do the extraction with only one field without conversion?
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- Scala
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Description
Hi,
First of all, thank you very much for this very useful library as this Cobol parser.
I am currently using it and I have a question. I am changing the way I read a cobol file. I have replaced a script we had by using this library.
One of the fields we want to extract without conversion, so I have used the debug option to true, because we have an ad hoc function to handle it.
This solution works fine, but it is generating all the columns without conversion, when it would be enough to generate only that column without conversion.
The question is if there is a way to do this, without having to use the debug option.
Thanks in advance.
Best regards,
Miguel
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