How to skip gqlgen to generate resolver for specific field
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Mô tả
### What happened?
I wanted gqlgen to skip creating a resolver for a specific field, in this case, to skip creating a resolver for the "permissions" field. Can gqlgen accomplish this?
```
type Role {
id: UUID!
name: String!
displayName: String!
description: String
permissions: [RolePermissions]
createdAt: Time!
updatedAt: Time!
}
type RolePermissions {
id: UUID!
parentId: UUID
name: String!
displayName: String!
children: [RolePermissions]!
createdAt: Time!
updatedAt: Time!
}
```
I added "resolver: false" to the gqlgen.yml configuration file, but it didn't work as expected. This feature seems to only force gqlgen to generate a resolver, not skip it.
```
Role:
model: models.Role
fields:
permissions:
resolver: false
```
### What did you expect?
When I ran the generate command, I expected gqlgen to skip creating the following resolver:
```
// Permissions is the resolver for the permissions field.
func (r *roleResolver) Permissions(ctx context.Context, obj *models.Role) ([]*graphqlModels.RolePermissions, error) {
panic(fmt.Errorf("not implemented: Permissions - permissions"))
}
```
### versions
- `go run github.com/99designs/gqlgen version`? v0.17.40
- `go version`? 1.21.6
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